Question

A. Guillaume puts a bottle of soft drink in a refrigerator and leaves it there until its temperature has dropped 15.7 K .

What is the magnitude of its temperature change |ΔT|= 15.7 K in degrees Celsius?

B. A glass flask whose volume is 1000 cm3 at a temperature of 0.300 ∘C is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52.0 ∘C , a volume of 8.25 cm3 of mercury overflows the flask.

If the coefficient of volume expansion of mercury is βHg = 1.80×10⁻⁴ /K , compute βglass, the coefficient of volume expansion of the glass.

Express your answer in inverse kelvins.

C. Consider an ideal gas at 27.0 degrees Celsius and 1.00 atmosphere pressure. Imagine the molecules to be uniformly spaced, with each molecule at the center of a small cube.

What is the length L of an edge of each small cube if adjacent cubes touch but don't overlap?

Express your answer numerically in meters.

D. Determine the temperature at which the Celsius and Fahrenheit scales give the same numerical reading (TC=TF).

E. A glass is filled to the brim with 360.0 mL of water at 100.0 ∘C.

If the temperature of glass and water is decreased to 20.0 ∘C, how much water could be added to the glass?

F. A storage tank at STP contains 26.9 kg of nitrogen (N2). What is the volume of the tank? What is the pressure if an additional 25.3 kg of nitrogen is added without changing the temperature?

G. 60.5 L of oxygen at 16.0 ∘C and an absolute pressure of 3.25 atm are compressed to 38.6 Land at the same time the temperature is raised to 51.0 ∘C. What will the new pressure be?

H.

What is the rms speed of nitrogen molecules contained in a 7.9 m3 volume at 2.9 atm if the total amount of nitrogen is 2300 mol ?

Express your answer to two significant figures and include the appropriate units.

Answer 1

A)

Change in temerature in bothe kelvin scale and degrees celcius are equal.

Therefore the magnitude of change in temperature in degrees celcius will be 15.7 degrees celcius.

B)

Apparent expansion of the liquid = Real expansion  - Volume expansion of the container

Real expansion of mercury

                                          

                                                   

Therefore the volume expansion of the container = Real expansion - Apparent expansion of the liquid

                                                                              =9.306 cm³ - 8.25 cm³

                                                                              = 1.056 cm³

But the volume expansion of the container is given by,

or

       

Please ask the other question in seperate questions