Question
In: Statistics and Probability
The mean life of a television set is 138 months with a variance of 324. If...
The mean life of a television set is 138 months with a variance of 324.
If a sample of 83 televisions is randomly selected, what is the probability that the sample mean would differ from the true mean by less than 5.4 months? Round your answer to four decimal places.
Solutions
Expert Solution
Solution :
Given that,
mean = 
= 138
standard deviation = 
= 18
=
/ 
n = 18 /
83 = 1.9758
= P[(-5.4) /1.9758 < (
-
)
/
< (5.4) / 1.9758)]
= P(-2.73 < Z < 2.73)
= P(Z < 2.73) - P(Z < -2.73)
= 0.9968 - 0.0032
= 0.9936
Probability = 0.9936
orchestra answered 2 years agoRelated Solutions
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