_ FeCl3 (aq) + _ NaOH (aq) --> Fe(OH)3 (_) + _ NaCl (___) Balance the...

___ FeCl₃ (aq) + ___ NaOH (aq) --> Fe(OH)₃ (___) + ___ NaCl (___)

Balance the reaction, and enter phases for the products. You do not need to submit this for this assignment, but it will help you solve the problem.

A 0.532 M NaOH solution is added to 39.4 mL of a 0.398 M FeCl₃ solution. What is the volume of NaOH in mL that must be added to completely react with the FeCl₃ solution?

Solutions

Expert Solution

The balanced equation is

FeCl3(aq) + 3NaOH(aq) Fe(OH)3(s) + 3NaCl(aq)

The volume of NaoH required

V1 = ?

M1 = 0.532 M NaOH

V2 = 39.4 mL

M2 = 0.398 M FeCl3

V1M1 = 3V2M2 [3 moles of NaOH is required to neutralize each mole of FeCl3]

V1 =

V1 = 47.044 / 0.532

V1 = 88.428 mL

Therefore, the volume of NaOH that must be added to completely react with the FeCl3 solution is 88.428 mL

queen_honey_blossom answered 1 year ago

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___ FeCl3 (aq) + ___ NaOH (aq) --> Fe(OH)3 (___) + ___ NaCl (___) Balance the...

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_ FeCl3 (aq) + _ NaOH (aq) --> Fe(OH)3 (_) + _ NaCl (___) Balance the...