Question

In: Statistics and Probability

The length of a 95% confidence interval for mean Children is which of the following? (Because...

The length of a 95% confidence interval for mean Children is which of the following? (Because of potential roundoff, choose the closest.)

data:

Person Gender Married Age Children Salary Spent
1 Male No 28 1 48600 750
2 Male Yes 35 2 75500 1980
3 Female No 33 2 58900 1820
4 Female Yes 53 1 92200 990
5 Female No 49 1 100700 1990
6 Male Yes 57 1 128900 1900
7 Female Yes 53 1 84900 1000
8 Female No 34 2 62500 2470
9 Male Yes 55 3 142700 2400
10 Male No 33 1 92300 2460
11 Female Yes 46 0 63700 440
12 Male Yes 48 1 114600 2330
13 Male No 30 1 60900 1800
14 Male Yes 33 3 70300 2010
15 Male Yes 50 0 149300 1860
16 Female No 41 0 75100 2180
17 Male No 36 1 71500 1020
18 Male Yes 44 2 86900 850
19 Male Yes 48 1 124600 1500
20 Male Yes 41 1 92600 1220
21 Female Yes 45 0 69600 1730
22 Male No 45 0 114300 2540
23 Female No 39 1 64100 1390
24 Male No 36 0 107900 2460
25 Male Yes 42 2 68200 680
26 Male No 39 1 84700 1360
27 Female No 53 3 76000 1510
28 Male No 46 1 119600 2260
29 Male Yes 38 2 70400 730
30 Male Yes 46 3 118300 2050
31 Male Yes 53 1 126900 1510
32 Male Yes 51 1 121200 1270
33 Male Yes 56 0 154700 3670
34 Female Yes 52 2 64900 330
35 Male No 29 2 54300 1060
36 Female No 36 2 51500 1560
37 Female Yes 56 5 70200 320
38 Male Yes 46 2 122000 3200
39 Male Yes 52 1 90400 910
40 Male No 51 3 94700 880
41 Male No 31 1 92900 3950
42 Female Yes 58 2 125300 2530
43 Female No 44 0 60200 570
44 Male Yes 61 2 140500 1120
45 Male Yes 55 0 118600 800
46 Female No 40 3 57700 1130
47 Male Yes 36 2 60300 960
48 Male No 52 1 110100 1360
49 Male Yes 43 1 95200 1690
50 Male Yes 50 1 137600 4060
51 Female No 53 1 115300 2760
52 Female Yes 42 3 67800 770
53 Male No 46 1 108100 1700
54 Male Yes 43 1 93700 2250
55 Male Yes 56 2 138500 2680
56 Male No 44 0 127100 2510
57 Female Yes 55 3 75800 810
58 Male No 45 0 109900 1810
59 Male No 37 0 59600 520
60 Male Yes 54 1 127200 2560
61 Male No 63 1 129800 1480
62 Male No 45 0 100000 1860
63 Female No 49 1 79000 2070
64 Female Yes 49 1 82200 1130
65 Male Yes 39 1 81500 2170
66 Male Yes 48 0 85100 1040
67 Male No 37 1 78100 1130
68 Male No 35 0 98600 2760
69 Female No 38 2 64800 1050
70 Male Yes 44 1 111400 2370
71 Female No 47 1 81700 1520
72 Male Yes 69 2 135000 1010
73 Male Yes 48 3 98000 830
74 Male Yes 62 0 142300 1570
75 Male Yes 43 1 81400 930
76 Female Yes 52 3 69200 450
77 Male Yes 57 2 125900 2060
78 Male Yes 54 1 126000 910
79 Male Yes 45 1 101500 1160
80 Male Yes 39 0 98900 2830
81 Female No 38 1 74200 2680
82 Male No 47 2 86600 820
83 Male Yes 60 1 141800 1670
84 Male No 29 0 86000 3620
85 Male Yes 42 2 125500 3530
86 Female No 47 2 83600 1030
87 Male Yes 56 0 112800 1540
88 Male No 44 1 101000 1730
89 Male No 49 2 95000 960
90 Male Yes 63 1 133000 2080
91 Male No 37 3 77800 1460
92 Male Yes 42 2 84800 730
93 Male No 47 2 99500 1530
94 Female No 49 0 65200 980
95 Female Yes 45 3 60100 390
96 Male No 33 0 80400 1660
97 Male Yes 48 3 84300 880
98 Male Yes 39 2 93000 2030
99 Male No 36 0 97900 3190
100 Male Yes 49 2 58100 120

Solutions

Expert Solution

We are to determine the 95% confidence interval for the mean of Children using the table given.

For the same, we first evaluate the mean and standard deviation. The formula for mean and standard deviation are:

where x_i are the values of children in the dataset and i ranges from 1-100 and refers to the number of persons or the number of rows. n is the total number of rows and hence n = 100

Substituting the values in the formula for mean, we get:

Next, we are to compute the standard deviation. For the same, we first compute for each of the x_i values.

Children ()

1 -0.33
2 0.67
2 0.67
1 -0.33
1 -0.33
1 -0.33
1 -0.33
2 0.67
3 1.67
1 -0.33
0 -1.33
1 -0.33
1 -0.33
3 1.67
0 -1.33
0 -1.33
1 -0.33
2 0.67
1 -0.33
1 -0.33
0 -1.33
0 -1.33
1 -0.33
0 -1.33
2 0.67
1 -0.33
3 1.67
1 -0.33
2 0.67
3 1.67
1 -0.33
1 -0.33
0 -1.33
2 0.67
2 0.67
2 0.67
5 3.67
2 0.67
1 -0.33
3 1.67
1 -0.33
2 0.67
0 -1.33
2 0.67
0 -1.33
3 1.67
2 0.67
1 -0.33
1 -0.33
1 -0.33
1 -0.33
3 1.67
1 -0.33
1 -0.33
2 0.67
0 -1.33
3 1.67
0 -1.33
0 -1.33
1 -0.33
1 -0.33
0 -1.33
1 -0.33
1 -0.33
1 -0.33
0 -1.33
1 -0.33
0 -1.33
2 0.67
1 -0.33
1 -0.33
2 0.67
3 1.67
0 -1.33
1 -0.33
3 1.67
2 0.67
1 -0.33
1 -0.33
0 -1.33
1 -0.33
2 0.67
1 -0.33
0 -1.33
2 0.67
2 0.67
0 -1.33
1 -0.33
2 0.67
1 -0.33
3 1.67
2 0.67
2 0.67
0 -1.33
3 1.67
0 -1.33
3 1.67
2 0.67
0 -1.33
2 0.67

Next, we square the values in the last column:

Children ()

1 -0.33 0.1089
2 0.67 0.4489
2 0.67 0.4489
1 -0.33 0.1089
1 -0.33 0.1089
1 -0.33 0.1089
1 -0.33 0.1089
2 0.67 0.4489
3 1.67 2.7889
1 -0.33 0.1089
0 -1.33 1.7689
1 -0.33 0.1089
1 -0.33 0.1089
3 1.67 2.7889
0 -1.33 1.7689
0 -1.33 1.7689
1 -0.33 0.1089
2 0.67 0.4489
1 -0.33 0.1089
1 -0.33 0.1089
0 -1.33 1.7689
0 -1.33 1.7689
1 -0.33 0.1089
0 -1.33 1.7689
2 0.67 0.4489
1 -0.33 0.1089
3 1.67 2.7889
1 -0.33 0.1089
2 0.67 0.4489
3 1.67 2.7889
1 -0.33 0.1089
1 -0.33 0.1089
0 -1.33 1.7689
2 0.67 0.4489
2 0.67 0.4489
2 0.67 0.4489
5 3.67 13.4689
2 0.67 0.4489
1 -0.33 0.1089
3 1.67 2.7889
1 -0.33 0.1089
2 0.67 0.4489
0 -1.33 1.7689
2 0.67 0.4489
0 -1.33 1.7689
3 1.67 2.7889
2 0.67 0.4489
1 -0.33 0.1089
1 -0.33 0.1089
1 -0.33 0.1089
1 -0.33 0.1089
3 1.67 2.7889
1 -0.33 0.1089
1 -0.33 0.1089
2 0.67 0.4489
0 -1.33 1.7689
3 1.67 2.7889
0 -1.33 1.7689
0 -1.33 1.7689
1 -0.33 0.1089
1 -0.33 0.1089
0 -1.33 1.7689
1 -0.33 0.1089
1 -0.33 0.1089
1 -0.33 0.1089
0 -1.33 1.7689
1 -0.33 0.1089
0 -1.33 1.7689
2 0.67 0.4489
1 -0.33 0.1089
1 -0.33 0.1089
2 0.67 0.4489
3 1.67 2.7889
0 -1.33 1.7689
1 -0.33 0.1089
3 1.67 2.7889
2 0.67 0.4489
1 -0.33 0.1089
1 -0.33 0.1089
0 -1.33 1.7689
1 -0.33 0.1089
2 0.67 0.4489
1 -0.33 0.1089
0 -1.33 1.7689
2 0.67 0.4489
2 0.67 0.4489
0 -1.33 1.7689
1 -0.33 0.1089
2 0.67 0.4489
1 -0.33 0.1089
3 1.67 2.7889
2 0.67 0.4489
2 0.67 0.4489
0 -1.33 1.7689
3 1.67 2.7889
0 -1.33 1.7689
3 1.67 2.7889
2 0.67 0.4489
0 -1.33 1.7689
2 0.67 0.4489

Summing the last column, we get:

Substituting this in the formula of standard deviation:

Now, the formula for the confidence interval is:

where z refers to the z-score that signifies the level of confidence. For 95% confidence interval, z = 1.96.

Substituting the values in the formula, we get:

Hence, the 95% Confidence Interval for the mean of Children is (1.13, 1.53).


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