How much energy would be needed to remove three electrons from a ground state beryllium atom?

The following are all ionization energies for beryllium.

		1^st Ionization		2^nd Ionization		3^rd Ionization		4^th Ionization
Energy (kJ/mol)		899		1757		14845		21000

Solutions

Expert Solution

energy required to remove 3 electrons from 1 mol Be atom = 899 + 1757 + 14845
= 17501 KJ
= 17,501,000 J

energy needed to remove 3 electrons from 1 atom,
E = 17,501,000 / (6.022*10^23)
= 2.906*10^-17 J
Answer: 2.906*10^-17 J

queen_honey_blossom answered 1 year ago

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