In: Chemistry
The following are all ionization energies for
beryllium.
1st Ionization | 2nd Ionization | 3rd Ionization | 4th Ionization | |||||
Energy (kJ/mol) | 899 | 1757 | 14845 | 21000 |
How much energy would be needed to remove three electrons from a
ground state beryllium atom?
energy required to remove 3 electrons from 1 mol Be atom
= 899 + 1757 + 14845
= 17501 KJ
= 17,501,000 J
energy needed to remove 3 electrons from 1 atom,
E = 17,501,000 / (6.022*10^23)
= 2.906*10^-17 J
Answer: 2.906*10^-17 J