Calculate the ground state energy of a helium atom in a box of
1cm on a side.
Solution: these are constants that we will see again and
again. I set c = 1.
In the ground state = 3, the helium mass is about 4 times the
proton mass, and using , the energy is roughly
E = [4(10^6)10(3)]/[2(4)(10^9)(10^16)] ~ 1.5 x 10^(-18)
ev.
This is a small energy, especially when compared to room
temperature energy of .025 ev. You can quickly verify that this is
also the spacing between the ground and first excited state. We can
calculate the associated classical velocity
.
Remember c = 1 but this is still quite slow (it’s about a
micrometer per second) in the grand scheme. I think it’s important
to do back of the envelope calculations like this to build
intuition about the magnitudes of things in a theory
.
2 : repeat the above calculation for diatomic oxygen in a 1m
on a side box. Find the classical velocity of the particle.
3: Take the oxygen molecule in the one centimeter box to deep
space where the temperature is 3K. Assume the particle is now at 3K
as well. Determine its classical speed and find an estimate (use
equipartition of energy arguments) for the particles quantum
state.