Question

The electron configuration of a neutral atom in the ground state is 1s^2 2s^2 2p^6 3s^2.

a) Write a complete set of quantum numbers for each of the electrons and name the element.

b) Is this element paramagnetic or diamagnetic? Please explain

Answer 1

Mg = 12 = 1s^2 2s^2 2p^6 3s^2

all the orbitals are paired . it is diamagnetic.

set of quantum numbers.

1 st electron    = >    n = 1 l=0 ml = 0 s = +1/2

2 =    n = 1 l=0 ml = 0 s = -1/2

3   =   n = 2, l=0 , ml = 0 , s = +1/2

4 =    n = 2, l=0 , ml = 0 , s = -1/2

5 =     n = 2, l=1 , ml = +1 , s = +1/2

6 =     n = 2, l=1 , ml = 0 , s = +1/2

7 =    n = 2, l=1 , ml = -1 , s = +1/2

8 = n = 2, l=1 , ml = +1 , s = -1/2

9 = n = 2, l=1 , ml = 0 , s = -1/2

10 =   n = 2, l=1 , ml = -1 , s = -1/2

11 = n = 3 l=0 , ml = 0 , s = +1/2

12 = n = 3 l=0 , ml = 0 , s = -1/2