Question

The electron configuration of an atom tells us how many electrons are in each orbital. For example, helium has two electrons in the 1s orbital. Therefore the electron configuration of He is 1s2

part a:

What is the ground-state electron configuration of a neutral atom of nickel?

Express your answer in condensed form, in order of increasing orbital energy. For example, [He]2s22p2 would be entered as [He]2s^22p^2 .

part b:

What is the ground-state electron configuration of the oxide ion O2−?

Express your answer in condensed form, in order of increasing orbital energy. For example, [He]2s22p2 should be entered as [He]2s^22p^2

part c:

Which element has the following configuration: [Xe]6s24f11?

Enter the chemical symbol for the element.

Answer 1

Ans

Part A

The atomic number of nickel is 28 which means it has 28 electrons.

So the electronic configuration of the neutral atom in condensed form is given as :

[Ar]3d^84s^2

Part b

The atomic number of oxygen is 8 , but O2- has 10 electrons.

So the electronic configuration will be [He]2s^22p^6

Part c

The configuration shows 54 + 13 = 67 electrons.

So the element corresponding to such a configuration is Holmium , chemical symbol : Ho