Based on the electron configuration and number of unpaired electrons, which are diamagnetic? Electron configuration of...

Based on the electron configuration and number of unpaired electrons, which are diamagnetic?

Electron configuration of Cu2+ is [Ar]3d(8)4s(2) and no. of unpaired electron is 2

Electron configuration of Mo4+ is [Kr]4d25s0 and no. of unpaired electron is 2

Electron configuration of Ce is [Xe] 4f1 5d1 6s2 and no. of unpaired electron is 2

Electron configuration of Sn is [Kr] 4d10 5s2 5p2 and no. of unpaired electron is 2

Electron configuration of V5+ is 1s2 2s2 2p6 3s2 3p6 and no. of unpaired electron is 0

Electron configuration of Sc2+ is 1s22s22p63s23p64s1 and no. of unpaired electron is 1

Solutions

Expert Solution

If there are unpaired electrons in the atom or ion then it is paramagnetic & if there are no unpaired electrons it is diamagnetic.

Electron configuration of Cu2+ is [Ar]3d(8)4s(2) and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of Mo4+ is [Kr]4d25s0 and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of Ce is [Xe] 4f1 5d1 6s2 and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of Sn is [Kr] 4d10 5s2 5p2 and no. of unpaired electron is 2 ------ para magnetic

Electron configuration of V5+ is 1s2 2s2 2p6 3s2 3p6 and no. of unpaired electron is 0 ----- diamagnetic

Electron configuration of Sc2+ is 1s22s22p63s23p64s1 and no. of unpaired electron is 1 ------ para magnetic

queen_honey_blossom answered 1 year ago

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