In: Statistics and Probability
The Dean of ASBE School of Business is concerned that grades in
the MBA program are distributed appropriately. Too many high grades
or too many low grades would pose a problem. We wish to test the
claim that the mean GPA of ASBE students is smaller than 3.3 at the
.005 significance level.
The null and alternative hypothesis would be:
The test is:
left-tailed
two-tailed
right-tailed
Based on a sample of 75 student grades, the sample mean GPA was
3.28 with a standard deviation of 0.02
The test statistic is: (Round to 3 decimals)
Based on this we:
A shareholders' group is lodging a protest against your company.
The shareholders group claimed that the mean tenure for a chief
exective office (CEO) was at least 9 years. A survey of 59
companies reported in The Wall Street Journal found a sample mean
tenure of 7.3 years for CEOs with a standard deviation of s=s= 5
years (The Wall Street Journal, January 2, 2007). You don't know
the population standard deviation but can assume it is normally
distributed.
You want to formulate and test a hypothesis that can be used to
challenge the validity of the claim made by the group, at a
significance level of α=0.01α=0.01. Your hypotheses are:
Ho:μ=9Ho:μ=9
Ha:μ<9Ha:μ<9
What is the test statistic for this sample?
test statistic = (Report answer accurate to 3 decimal
places.)
What is the p-value for this sample?
p-value = (Report answer accurate to 4 decimal
places.)
The p-value is...
This test statistic leads to a decision to...
As such, the final conclusion is that...
Given:
Claim : Ghe mean GPA of ASBE students is smaller than 3.3 at significance level 0.005
The null and alternative hypotheses is
Ho : μ = 3.3
Ha : μ < 3.3
Since alternative hypothesis contain < sign,
The test is left-tailed test
Sample size, n = 75
Sample mean, = 3.28
Standard deviation, s = 0.02
Test statistics :
t = - μ/s/√n
= 3.28 - 3.3/0.02/√75
= -8.660
Test statistics is t = -8.660
Degree of freedom, df = n-1 = 75-1 = 74
At 0.005 the critical value of a t with degree of freedom, df = 74 is -2.644
Rejection rule:
Reject Ho if to < -2.644
Since to < -2.644 , = 0.005 we reject null hypothesis.
Decision: Reject null hypothesis.
Conclusion : There is sufficient evidence to conclude that the mean GPA of ASBE students is smaller than 3.3 at the .005 significance level.
2) Given:
The null and alternative hypothesis is
Ho : μ = 9
Ha : μ < 9
Sample size, n = 59
Sample mean, = 7.3
Standard deviation, s= 5
Test statistics is
t = - μ/s/√n
= 7.3 - 9/5/√59
= -2.612
Test statistics is t = -2.612
Degree of freedom, df = n-1 = 59-1 = 58
At 0.01 significance level the critical value of t with degree of freedom, df = 58 is -2.392
Rejection rule:
Reject Ho if to < -2.392
Since to < -2.392 , we reject null hypothesis.
Decision: Reject null hypothesis.
Conclusion: