The input capacitance to an STM amplifier is 2pF. The desired frequency response is 5kHz (i.e.,...

The input capacitance to an STM amplifier is 2pF. The desired frequency response is 5kHz (i.e., 0.0002 s time constant). Choose the largest current to voltage conversion resistor this constraint allows, and then calculate the smallest measureable current (i.e. just equal to the Johnson noise) at the target bandwidth. The angular'frequency, ω, at which the response of an RC integrator falls by 3dB is given by ωRC=1. I need step by step equation with explanation please. Thank you

Expert Solution

genius_generous answered 2 years ago

In a differential amplifier, the noninverting input is 3cos(600t + 45°) mV and the inverting input...

In a differential amplifier, the noninverting input is 3cos(600t + 45°) mV and the inverting input is 4cos (600t - 45°) mV. The ooutput is vo = 3cos (600t - 45°) + 4.004cos (600t - 45°) V. The CMRR is of? The unit must be in dB. Is vo= 3cos(600t + 45 ◦ ) + 4.004cos(600t - 45◦) V instead of: vo = 3cos(600t - 45 ◦ ) + 4.004cos(600t - 45 ◦ ) V

In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the...

In a differential amplifier, the noninverting input is 3 cos (600t + 45◦) mV and the inverting input is 4cos (600t - 45◦) mV. The output is vo = 3cos (600t + 45◦) + 4.004cos (600t - 45◦) V. The CMRR is_____ dB.

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In a differential amplifier, the non-inverting input is 3 cos (600t + 45◦) mV and the...

In a differential amplifier, the non-inverting input is 3 cos (600t + 45◦) mV and the inverting input is 4cos (600t - 45◦) mV. The output is vo = 3cos (600t + 45◦) + 4.004cos (600t - 45◦) V. The CMRR is of ____ dB

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