Consider the titration of 233 mL of 0.855 M propanoic acid, CH3CH2COOH, Ka = 1.3 x...

Consider the titration of 233 mL of 0.855 M propanoic acid, CH3CH2COOH, Ka = 1.3 x 10^-5 with 1.125 M KOH for the following question.

What is the pH of the solution when 249.7 mL of the 1.125 M KOH has been added to the 0.855 M propanoic acid solution?

(This question was a 3-part problem where you also had to find the pH at the equivalence point but I already figured those parts out)

Expert Solution

queen_honey_blossom answered 2 years ago

Consider the titration of 233 mL of 0.855 M propanoic acid, CH3CH2COOH, Ka = 1.3 x...

Consider the titration of 233 mL of 0.855 M propanoic acid, CH3CH2COOH, Ka = 1.3 x 10^-5 with 1.125 M KOH for the following question. What is the pH of the solution at the equivalence point? (answer is somewhere around 9)

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Question

Consider the titration of 233 mL of 0.855 M propanoic acid, CH3CH2COOH, Ka = 1.3 x...

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Expert Solution

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Consider the titration of 233 mL of 0.855 M propanoic acid, CH3CH2COOH, Ka = 1.3 x...

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