0.5 Kg of air at t1 = 327 0C and the specific volume v1 = 0.2...

0.5 Kg of air at t1 = 327 ⁰C and the specific volume v1 = 0.2 m³/Kg is enclosed in a cylinder under a piston. The gas slowly expands with no friction to the temperature t2 = 0 ⁰C and the specific volume v2 =0.65 m³/Kg (polytrophic process). Find the work and heat of the process and change in internal energy of gas. Determine the initial and final pressure of the gas. The isentropic exponent and particular gas constant for air are equal to k=1.4 and R=287 J/KgK, respectively.

Expert Solution

samet mamat answered 2 years ago

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