Question

1)Consider water at 500 kPa and a specific volume of 0.2 m3/kgm3/kg. What is the temperature (in °C)?

2)Consider water at 500 kPa and a specific volume of 0.2 m3/kgm3/kg. What is the quality (on a 0 to 1 scale)?

3)Consider water at 1400 kPa and 200°C. What is the specific volume (in m3/kgm3/kg)?

Answer 1

(1)

Using Table A-5 (Saturated water - Pressure table);

• at P = 500 kPa;

T_sat = 151.83^oC

v_f = 0.001093 m³/kg

v_g = 0.37483 m³/kg

Given,

v = 0.2 m³/kg

On comparing we can see that v lies between v_f and v_g;

v_f < v < v_g

Hence,

State = Saturated mixture

and

T = T_sat = 151.83^oC

...(Answer)

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(b)

Use part-a for the reference data;

...(Answer)

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(c)

Using Table A-5 (Saturated water - Pressure table);

• at P = 1400 kPa;

T_sat = 195.04^oC

Given.

T = 200^oC

On comparing we can see that T is more than T_sat, hence;

State = Superheated

Using Table A-6 (Superheated water);

• at P = 1400 kPa and T = 200^oC;

v = 0.14303 m³/kg

...(Answer)