Given the data:
PbO(s), Df Hq = -217.3 kJ
mol–1, Sq = +68.7 J mol–1
K–1
PbO2(s), Df Hq = -277.0
kJ mol–1, Sq = +68.6 J
mol–1 K–1
O2(g), Df Hq= 0.00 kJ
mol–1, Sq = +205 J mol–1
K–1
calculate the standard free energy change,
DrGq, for the reaction:
PbO(s) + ½ O2(g) ® PbO2(s)
Select one:
a. +1.45 kJ mol–1
b. –29.1 kJ mol–1
c. –68.3 kJ mol–1
d. –90.3 kJ m