Question

Discusses how you would find out how to keep an outfielder on a baseball team if you had to cut two players of three. The averages of the three players are: Player 1: 333, Player 2: 301, Player 3: 296. Player one hit 6 home runs, player 2 hit 4 home runs, and player three hit 16 home runs. Which statistic is a better evaluation of player performance why? How did you determine this by statistical testing?

Answer 1

Since ,statistical constants enables us to comprehend in a single effort the significance of the whole concentration of the values in the central part of the distribution.

In this example we are given the average of three players and max. frequency occuring for home runs.

Since, average is the better method to determine this average should be used to better evaluate the performance of the players.

we can use z-statistic for the proportions.

(for player 1 and 2) similarly for player 2&3 and 1&3

taking the null hypothesis the performance of two players is equal and Alternative hypothesis: performance of player 1 is more than 2

and similarly for 2&3 and 1&3

for one tailed test: if calculated value of Z is less than the critical value of Z at given level of significance the null hypothesis is rejected at that level of significance.( for left tail for example)

I HOPE ITS CLEAR!!!