Nylon (C12H22N2O2) burns in pure oxygen. What is the equivalence ratio? What is the coefficients to the actual reaction ?

The actual chemical reaction for the given burning condition is C12H22N2O2+V1*O2 -> V2*CO2+V3*H2O+V4*HCN

Solutions

Expert Solution

C12H22N2O2+V1*O2 -> V2*CO2+V3*H2O+V4*HCN

The reaction will be

C12H22N2O2 + 15 O2 ----> 10 CO2 + 10 H2O + 2 HCN (Balanced Reaction)

The equivalence ratio = the mass ratio of air to fuel present in a combustion process

mass of air = 15* 32 + 10*(44) =920 grams

mass of Nylon = 1* 226 = 226 grams

Therefore Equivalence ratio = mass of air / mass of fuel = 920/226 = 4.07 :1

queen_honey_blossom answered 1 year ago

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