Question
In: Chemistry
Balance the following redox reaction if it occurs in H2SO4. What are the coefficients in front...
Balance the following redox reaction if it occurs in
H2SO4. What are the coefficients in front of
H2O and Cr2(SO4)3 in
the balanced reaction?
C3H8O2(aq) +
K2Cr2O7(aq) →
C3H4O4(aq) +
Cr2(SO4)3(aq)
Can someone please explain everything step by step since how to determine oxidation numbers and half reactions?
Solutions
Expert Solution
3 C3H8O2 + 4
K2Cr2O7 + 16
H2SO4
3
C3H4O4 + 4
Cr2(SO4)3 + 4
K2SO4 + 22 H2O
Explanation is as below:
Oxidation : C3H8O2
C3H4O4 + 8e-
Reduction : K2Cr2O7 +
6e-
Cr2(SO4)3
While balancing the number of electrons, the total number of
electron transferred is 24.
So the balanced oxidation reaction is
3C3H8O2
3C3H4O4 + 24
e-
and the reduction reaction is
4K2Cr2O7 + 24
e-
4Cr2(SO4)3
In order to balance the equation, we have to add the amount of
oxygen missing in the oxidation reaction and and the amount of
sulfuric acid (H2SO4) in the reduction reaction.
6H2O +
3C3H8O2
3C3H4O4 + 24 e- +
24H+
-------------------------------------------------(1)
16H2SO4 +
4K2Cr2O7 + 24 e- +
24H+
4Cr2(SO4)3
+ 28H2O +4K2SO4
-----------------------(2)
Adding equation (1) and (2), the electrons and the protons
(H+) will cancel out, the water coefficient will
subtract and become 22.
Thus, the correct balanced reaction is
3
C3H8O2 + 4
K2Cr2O7 + 16
H2SO4 3
C3H4O4 + 4
Cr2(SO4)3 + 4
K2SO4 + 22 H2O
queen_honey_blossom answered 2 years agoRelated Solutions
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