In: Chemistry
Pure copper may be produced by the reaction of copper(I) sulfide with oxygen gas as follows:
Cu2S(s) + O2(g) → 2Cu(s) + SO2(g)
If 0.490 kg of copper(I) sulfide reacts with excess oxygen, what mass of copper metal may be produced?
A. |
0.980 kg |
|
B. |
0.490 kg |
|
C. |
0.391 kg |
|
D. |
0.196 kg |
|
E. |
0.0978 kg |
Molar mass of Cu2S = 159 g/mol
mass of Cu2S = 0.49 Kg = 0.49*1000 = 490g
number of moles of Cu2S = mass/molar mass
= 490/159
= 3.08 mol
1 mol of Cu2S gives 2moles of Cu
so,
number of moles of Cu formed = 2*3.08 mol = 6.16mol
Molar mass of Cu = 63.5 g/mol
Mass of Cu = molar mass * number of moles
= 63.5 * 6.16
= 391 g
= 0.391 Kg
Answer: 0.391 Kg