In: Chemistry
Oxalic acid , HOOCCOOH, is a diprotic acid with Ka1= 0.056 and Ka2=1.5x10-4. Determine the equilibrium [HOOCCOOH] in a solution with an initial concentration of 0.116 M oxalic acid
. HOOCCOOH = HOOCCOO- + H+
HOOCCOO- = -OOCCOO- + H+
HOOCCOOH ------------>HOOCCOO- + H+
I 0.116 0 0
C -x +x +x
E 0.116-x +x +x
Ka1 = [HOOCCOO-][H+]/ [HOOCCOOH]
0.056 = x*x/(0.116-x)
0.056*(0.116-x) = x^2
x = 0.057
[HOOCCOOH] = 0.116-x = 0.116-0.057 = 0.059 M