Question

In: Statistics and Probability

Consider the population described by the probability distribution shown in the table. The random variable x...

Consider the population described by the probability distribution shown in the table. The random variable x is observed twice. If these observations are independent, all the different samples of size 2 and their probabilities are shown in the accompanying table. Complete parts a through e below.

x 1 2 3 4 5
p(x) 0.4 0.1 0.2 0.2 0.1

x (bar over x)

1.0 1.5 2.0 2.5 3 3.5 4 4.5 5
p(x) (bar over x) 0.16 0.08 0.17 0.2 0.16 0.1 0.08 0.04 0.01
Sample Mean Probability Sample Mean Probability
1, 1 1.0 0.16 3, 4 3.5 0.04
1, 2 1.5 0.04 3, 5 4.0 0.02
1, 3 2.0 0.08 4, 1 2.5 0.08
1, 4 2.5 0.08 4, 2 3.0 0.02
1, 5 3.0 0.04 4, 3 3.5 0.04
2, 1 1.5 0.04 4, 4 4.0 0.04
2, 2 2.0 0.01 4, 5 4.5 0.02
2, 3 2.5 0.02 5, 1 3.0 0.04
2, 4 3.0 0.02 5, 2 3.5 0.01
2, 5 3.5 0.01 5, 3 4.0 0.02
3, 1 2.0 0.08 5, 4 4.5 0.02
3, 2 2.5 0.02 5, 5 5.0 0.01
3, 3 3.0 0.04

a.) Find the sampling distribution of s^2. Type the answers in ascending order for s^2

s^2
P(s^2)

(type as integers or decimals)

b. Find the population variance:

c.) Find the sampling distribution of the sample standard deviation.

s
P(s)

Solutions

Expert Solution

Variance for each sample will be calculated using excel formula "=var()". Following table shows the sample variances and corresponding probabiltes:

Samples Probabilites Sample variances, s^2 P(s^2)
1 1 0.16 0 0.16
1 2 0.04 0.5 0.04
1 3 0.08 2 0.08
1 4 0.08 4.5 0.08
1 5 0.04 8 0.04
2 1 0.04 0.5 0.04
2 2 0.01 0 0.01
2 3 0.02 0.5 0.02
2 4 0.02 2 0.02
2 5 0.01 4.5 0.01
3 1 0.08 2 0.08
3 2 0.02 0.5 0.02
3 3 0.04 0 0.04
3 4 0.04 0.5 0.04
3 5 0.02 2 0.02
4 1 0.08 4.5 0.08
4 2 0.02 2 0.02
4 3 0.04 0.5 0.04
4 4 0.04 0 0.04
4 5 0.02 0.5 0.02
5 1 0.04 8 0.04
5 2 0.01 4.5 0.01
5 3 0.02 2 0.02
5 4 0.02 0.5 0.02
5 5 0.01 0 0.01

Following table shows the sampling distribution of sample variances:

s^2 P(s^2)
0 0.26
0.5 0.24
2 0.24
4.5 0.18
8 0.08

(b)

Following table shows the calculations for population variances:

x p(x) xp(x) x^2*p(x)
1 0.4 0.4 0.4
2 0.1 0.2 0.4
3 0.2 0.6 1.8
4 0.2 0.8 3.2
5 0.1 0.5 2.5
Total 2.5 8.3

The population variance is:

c)

For sampligng distribution of SD we need to square root of variances. Following table shows the same:

s P(s)
0 0.26
0.7071 0.24
1.4142 0.24
2.1213 0.18
2.8284 0.08

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