Question
In: Electrical Engineering
When running at 4000rpm with an applied voltage of 42v, a DC permanent magnet motor develops...
When running at 4000rpm with an applied voltage of 42v, a DC permanent magnet motor develops 23.1W of output power. The motor has a theoretical no-load speed of 6000rpm at an applied voltage of 42v.
What is the motor output torque at 4000rpm in N-m, What is the motors theoretical back-EMF constant, What is the motors theoretical torque constant, What is the motors theoretical stall torque, What is the motors armature resistance, What is the motors efficiency at 4000rpm when operated at 42v.
Solutions
Manojponduru answered 1 year agoRelated Solutions
23 hp, dc shunt motor is running at 1000 rpm when the armature voltage is 600...
23 hp, dc shunt motor is running at 1000 rpm when the armature
voltage is 600 V. The armature resistance of the motor is 0.8 ohm,
and the field resistance is 900 ohm. The efficiency of the motor at
full load is 92 %.
a) Calculate the value of the resistance of the dynamic braking
at full load. The armature current should be limited to 150% of the
rated value.
b) If the motor operated in regenerative braking at a...
: A dc motor develops 55 N-m torque at a speed of 600 rad/s when 12...
: A dc motor develops
55 N-m torque at a speed of 600 rad/s when 12 volts are applied. It
stalls out at this voltage with 100 N- m of torque. If the inertia
and damping of the armature are 7 kg-m2 and 3 N-m -s/rad,
respectively, find the transfer function, G(s) = θL(s)/Ea(s), of
this motor if it drives an inertia load of 105 kg-m2 through a gear
train, as shown in the figure 11.
(a) In DC motor, quadrant of operation can be defined by the armature voltage and current...
(a)
In DC motor, quadrant of operation can be defined by the
armature voltage and
current of the motor. By using an appropriate diagram, briefly
explain the
definition of all four quadrant of operation based on armature
voltage and current.
(b)
A chopper is used to control speed of 45.36 kW, 1750 rpm, 240 V,
189 A
permanent magnet DC motor with 0.01 Ω armature resistance. This
chopper-fed
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mode...
A powerful bipolar permanent magnet stepper motor used for positioning a valve has a rated current...
A powerful bipolar permanent magnet stepper motor used for
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resistance of 60 mΩ, a winding inductance of 0.77 mH, a 0.16Nm
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second [sps]: 8 N.m. Its step rate is 200 steps per revolution, and
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The motor is chopper-driven at 65 V and it develops a torque of
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Design a power supply to deliver 4 to 9 Vdc adjustable voltage to control DC motor...
Design a power supply to deliver 4 to 9 Vdc adjustable voltage
to control DC motor speed. Motor power at maximum load is 20W at
maximum speed (maximum voltage). Supply is 12V car battery with
70Ah capacity. How long the battery will last at maximum load and
maximum speed? Add a 13.8Vdc communications power supply to
continuously charge the battery at 500mA.
Starting from the dynamic equations of the PM DC motor obtain the voltage-to-speed transfer function in...
Starting from the dynamic equations of the PM DC motor obtain
the voltage-to-speed transfer function in s-domain. Draw the block
diagram.
Starting from the dynamic equations of the PM DC motor obtain the voltage-to-speed transfer function in...
Starting from the dynamic equations of the PM DC motor obtain
the voltage-to-speed
transfer function in s-domain. Draw the block diagram.
Problem: A PM DC motor has the following parameters: Rated Power 10 hp; Rated armature voltage...
Problem: A PM DC motor has the following parameters:
Rated Power 10 hp;
Rated armature voltage 230 V-DC;
Rated RPM: 1800;
Armature Resistance: 0.2 Ohm
Armature Inductance: 0.005 H
Inertia (motor plus mechanical load): 0.1 kgm^2;
Viscous friction coefficient: 0.015 Nms
1. Compute the voltage constant of the motor. Also compute the
rated current and rated torque of the motor (obtained at the rated
RPM). If the motor is supplied by 230 V across the armature, and
the only torque...
A 6-pole, 50 Hz, 3-phase induction motor running on full load develops a useful torque of...
A 6-pole, 50 Hz, 3-phase induction motor running on full load develops a useful torque of 160 Nm when the rotor emf makes 120 complete cycles per minute. The windage and friction loss is 1005.30 Watt. It is assumed; the core loss is lumped together with the windage and friction loss. The total stator loss is given to be 800 Watt. Compute: a) Shaft power output, b) The copper loss in the rotor winding,c) The input power to the motor, and d) The...
Compare the brushed motor (DC motor) and a brushless motor (Induction Motor) in FIVE aspects.
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(Induction Motor) in FIVE aspects.
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