A powerful bipolar permanent magnet stepper motor used for positioning a valve has a rated current...

A powerful bipolar permanent magnet stepper motor used for positioning a valve has a rated current of 13 A, a winding resistance of 60 mΩ, a winding inductance of 0.77 mH, a 0.16Nm detent torque, holding torque: 9.5 N.m, torque at 50 steps per second [sps]: 8 N.m. Its step rate is 200 steps per revolution, and the rotor inertia is 0.7x 10- 3 kg.m2.

The motor is chopper-driven at 65 V and it develops a torque of 2.2 N.m at 10000 sps. Calculate:

The speed [rpm] and power [hp] of the motor when it is running at 10000 sps.
The time constant of the windings
The time to reach 13 A when 65 V is applied to the winding

Expert Solution

Manojponduru answered 3 months ago

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