How many ml of 0.100M NaOH solution are required to neutralize 15.0 ml of 0.200M H3PO4?

Expert Solution

3NaOH + H3PO4 -----------> Na3PO4 + 3H2O

3 moles 1 mole

NaOH H3PO4

M1 = 0.1M M2 = 0.2M

V1 = V2 = 15ml

n1 = 3 n2 = 1

M1V1/n1 = M2V2/n2

V1 = M2V2n1/M1n2

= 0.2*15*3/0.1*1 = 90ml

volume of NaOH = 90ml

queen_honey_blossom answered 2 years ago

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