In: Math
Write the point-slope form of the line's equation satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation.
Slope =3, passing through (6 ,2)
What is the point-slope form of the equation of the line?
__?
(Simplify your answer. Use integers or fractions for any numbers in the equation.)
What is the slope-intercept form of the equation of the line?
__?
(Simplify your answer. Use integers or fractions for any numbers in the equation.)
Solution :
Given : Slope = 3, Passing through ( x1, y1) = ( 6, 2)
Point - slope form of the equation of line
y - y1 = m( x - x1 )
y - 2 = 3( x - 6 )
Switch sides
3( x - 6 ) = y - 2
3x - 18 = y - 2
3x - y - 18 + 2 = 0
3x - y - 16 = 0
Hence, the Point - slope form of the equation of line is
3x - y - 16 = 0
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Solution :
Substitute the known values into the slope-intercept formula, and then solve for the unknown value of b.
Back substitute the value of the slope and the solved value of the y-intercept into y=mx+b