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Write the point-slope form of the line's equation satisfying the given conditions. Then use the point-slope...

Write the point-slope form of the line's equation satisfying the given conditions. Then use the point-slope form of the equation to write the slope-intercept form of the equation.

Slope =3, passing through (6 ,2)

What is the point-slope form of the equation of the line?

__?

(Simplify your answer. Use integers or fractions for any numbers in the equation.)

What is the slope-intercept form of the equation of the line?

__?

(Simplify your answer. Use integers or fractions for any numbers in the equation.)

Solutions

Expert Solution

Solution :

Given : Slope = 3, Passing through ( x₁, y₁) = ( 6, 2)

Point - slope form of the equation of line

y - y₁ = m( x - x₁ )

y - 2 = 3( x - 6 )

Switch sides

3( x - 6 ) = y - 2

3x - 18 = y - 2

3x - y - 18 + 2 = 0

3x - y - 16 = 0

Hence, the Point - slope form of the equation of line is

3x - y - 16 = 0

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Solution :

Substitute the known values into the slope-intercept formula, and then solve for the unknown value of b.

Back substitute the value of the slope and the solved value of the y-intercept into y=mx+b

milcah answered 1 year ago

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