Using E° = .697 V and the Nernst equation, calculate the concentration of Hg2+ in a...

Using E° = .697 V and the Nernst equation, calculate the concentration of Hg2+ in a sample of pond water if [Sn2+] = 0.500 M, [Sn4+] = 0.305 M and Ecell = 0.711 V.

Expert Solution

Sn^2+ (aq) ---------------> Sn^4+ + 2e^- E0 = -0.15v

Hg^2+ (aq) + 2e^- ------------> Hg(l) E0 = 0.85v

---------------------------------------------------------------------------------

Sn^2+(aq) + Hg^2+ (aq) ------------------> Sn^4+(aq) + Hg(l) E0cell = 0.697v

n =2

Ecell = E0cell -0.0592/n logQ

0.711 = 0.697-0.0592/2 log[Sn^4+]/[Sn^2+][Hg^2+]

0.711 = 0.697 -0.0296 log0.305/0.5*[Hg^2+]

0.711-0.697 = -0.0296log0.305/0.5*[Hg^2+]

0.014 = -0.0296log0.305/0.5*[Hg^2+]

log0.305/0.5*[Hg^2+] = -0.014/0.0296

log0.305/0.5*[Hg^2+] = 0.4729

0.305/0.5*[Hg^2+] = 10^0.4729

0.305/0.5*[Hg^2+] = 2.9709

[Hg^2+] = 0.305/0.5*2.9709

[Hg^2+] = 0.205M >>>>>answer

queen_honey_blossom answered 1 year ago

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