Question

In: Chemistry

Using E° = .697 V and the Nernst equation, calculate the concentration of Hg2+ in a...

Using E° = .697 V and the Nernst equation, calculate the concentration of Hg2+ in a sample of pond water if [Sn2+] = 0.500 M, [Sn4+] = 0.305 M and Ecell = 0.711 V.

Solutions

Expert Solution

   Sn^2+ (aq) ---------------> Sn^4+ + 2e^-     E0 = -0.15v

    Hg^2+ (aq) + 2e^- ------------> Hg(l)             E0   = 0.85v

---------------------------------------------------------------------------------

Sn^2+(aq) + Hg^2+ (aq) ------------------> Sn^4+(aq) + Hg(l)          E0cell = 0.697v

    n =2

Ecell   = E0cell -0.0592/n logQ

0.711   = 0.697-0.0592/2 log[Sn^4+]/[Sn^2+][Hg^2+]

0.711      = 0.697 -0.0296 log0.305/0.5*[Hg^2+]

0.711-0.697    = -0.0296log0.305/0.5*[Hg^2+]

0.014             = -0.0296log0.305/0.5*[Hg^2+]

log0.305/0.5*[Hg^2+]    = -0.014/0.0296

log0.305/0.5*[Hg^2+]     = 0.4729

0.305/0.5*[Hg^2+]           = 10^0.4729

0.305/0.5*[Hg^2+]            = 2.9709

[Hg^2+]                           = 0.305/0.5*2.9709

[Hg^2+]                           = 0.205M >>>>>answer


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