Question

In: Chemistry

Calculate the concentration of free mercury (II) ion, [Hg2+], in an aqueous solution that is initially...

Calculate the concentration of free mercury (II) ion, [Hg2+], in an aqueous solution that is initially 0.16 M Hg(NO3)2 and 3.2 M NaCl given that the Kf of HgCl42- is 1.7*1016.

The answer is 2.2*10-19 M, how?

Solutions

Expert Solution

The equation for the complexation reaction is

        Hg+2               + 4 Cl-         -------> [HgCl4]-2

      0.16M                  3.2M                       0       initial concentrations

   0.16-x                   3.2-4x                       x       after reaction

Thus Kf = x/[(0.16-x)(3.2-4x)4 which is equal to 1.7 x 1016

Soving for x we get


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