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What is the equilibrium constant for the reaction of AgCl(s) with concentrated HCN?

What is the equilibrium constant for the reaction of AgCl(s) with concentrated HCN? The Ksp of AgCl is 1.8 × 10−10 and the Kf of Ag(CN)2− is 1.0 × 1021.

Solutions

Expert Solution

AgCl-----------> Ag+ Cl- (1) KSp =[Ag+] [Cl-] =1.8*10-10

Ag + +2CN- --------> Ag(CN)-2    (2) Kf= 1*1021    =   [Ag(CN)-2/ [Ag+][CN-]2

Kf*Ksp= [Ag+] [Cl-]*Ag[CN)-2/ [Ag+ [CN]-2= [CL-] [Ag(CN)-2/ [CN-]2 = 1.8*10-10*1*1021 =1.8*1011

Adding Eq.1 and 2 gives

AgCl +2CN-   -------> Ag(CN)-2 +CL- =1.8*1011

queen_honey_blossom answered 2 years ago
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