In: Chemistry
Express the equilibrium constant for the following
reaction.
5P4O10(s) ⇋ 5P4(s) + 25O2(g)
5P4O10(s) ⇋ 5P4(s) + 25O2(g)
rate of forward reaction = Kf for solids [P4O10] = 1
rate of back ward reaction = Kb[O2]25
at equilibrium reate of forward reaction = rate of back ward reaction
Kf = Kb[O2]25
Kf/Kb [O2]25
Kc = [O2]25 >>>>>answer