Question

In: Chemistry

Express the equilibrium constant for the following reaction. 5P4O10(s) ⇋  5P4(s) + 25O2(g)

Express the equilibrium constant for the following reaction.

5P4O10(s) ⇋  5P4(s) + 25O2(g)

Solutions

Expert Solution

5P4O10(s) ⇋  5P4(s) + 25O2(g)

rate of forward reaction = Kf                             for solids [P4O10] = 1

rate of back ward reaction = Kb[O2]25              

at equilibrium reate of forward reaction = rate of back ward reaction

                                       Kf           = Kb[O2]25     

                                      Kf/Kb               [O2]25

                                        Kc                = [O2]25 >>>>>answer


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