Question

In: Chemistry

A doctor orders 170. mL of 4 % (m/v) ibuprofen. If you have 10.% (m/v)...

A doctor orders 170. mL of 4 % (m/v) ibuprofen. If you have 10. % (m/v) ibuprofen on hand, how many milliliters do you need? Express the volume to two significant figures and include the appropriate units. A doctor orders 170. mL of 4 % (m/v) ibuprofen. If you have 10. % (m/v) ibuprofen on hand, how many milliliters do you need? Express the volume to two significant figures and include the appropriate units.

A doctor orders 170. mL of 4 % (m/v) ibuprofen. If you have 10. % (m/v) ibuprofen on hand, how many milliliters do you need? Express the volume to two significant figures and include the appropriate units.

You need to prepare a 2.20 M solution of sodium hydroxide (molar mass of sodium hydroxide = 40.00 g/mol ), but you only have a 10 mL graduated cylinder and a 25 mL beaker. Complete the following sentences regarding the concentration of the prepared solution. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

You need to prepare a 2.20 M solution of sodium hydroxide (molar mass of sodium hydroxide = 40.00 g/mol ), but you only have a 10 mL graduated cylinder and a 25 mL beaker. Complete the following sentences regarding the concentration of the prepared solution. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

Solutions

Expert Solution

1)

from above data that

first calculate mass of ibuprofen in170 ml 4% solution

mass of solute = % by mass of solute Xvolume of solution / 100

= 4 X 170 / 100 = 6.8

if we have 10 % ibuprofen then

volume of solution = mass of solute X 100 / % mass of solute

= 6.8 X100 / 10 = 68 ml

we need 68 ml ibuprofen

2)

from above data that

1. Molarity = Number of Moles/Volume

Number of Moles = 2.2*0.01 = 2.2*10-2

Mass of sodium hydroxide   = 40*2.2*10-2 = 0.88 g = 0.9 g (i.e. Last choice)

2.

As you know everything has volume and mass. So when you add 0.9 g of Solute to water it will occupy some volume. So volume of solution will be greater than 10 mL.

3.

Now as our effective volume is greater than 10 mL so concentration wil decrese as Conc = Mols/Volume. So our effective concentration will be less than 2.2 M.


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