Question

The following data represent the muzzle velocity​ (in feet per​ second) of rounds fired from a​ 155-mm gun. For each​ round, two measurements of the velocity were recorded using two different measuring​ devices, resulting in the following data. Complete parts​ (a) through​ (d) below. Observation 1 2 3 4 5 6 A 791.9 794.2 793.6 793.5 790.4 790.3 B 792.1 790.9 796.7 792.3 795.3 788.9 ​(a) Why are these​ matched-pairs data? A. All the measurements came from rounds fired from the same gun. B. The same round was fired in every trial. C. The measurements​ (A and​ B) are taken by the same instrument. D. Two measurements​ (A and​ B) are taken on the same round. Your answer is correct. ​(b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the alpha equals 0.01 level of​ significance? ​Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. Let diequalsAiminusBi. Identify the null and alternative hypotheses. Upper H 0​: mu Subscript d equals 0 Upper H 1​: mu Subscript d not equals 0 Determine the test statistic for this hypothesis test. t0equals nothing ​(Round to two decimal places as​ needed.)

Need P-Value

Conclusion regarding H0

Conducting a 99% confidence interval for lower and upper bound

Interpret the confidence interval

Draw a boxplot and tell the visual evidence to support it. I need the answers for these as well please.

Answer 1

Observation	A	B	di= A - B	di- d_bar	(di- d_bar)^2
1	791.9	792.1	-0.2	0.18	0.0324
2	794.2	790.9	3.3	3.68	13.5424
3	793.6	796.7	-3.1	-2.72	7.3984
4	793.5	792.3	1.2	1.58	2.4964
5	790.4	795.3	-4.9	-4.52	20.4304
6	790.3	788.9	1.4	1.78	3.1684
SUM=			-2.3		47.0684
MEAN=			-0.38

We are 99 % confident that the true population mean of difference lies between -5.4304 and 4.6704

BOXPLOT: