Question

In: Statistics and Probability

Let X be a Bin(n, p) random variable. Show that Var(X) = np(1 − p). Hint:...

Let X be a Bin(n, p) random variable. Show that Var(X) = np(1 − p). Hint: First compute E[X(X − 1)] and then use (c) and (d).

(c) Var(X) = E(X^2 ) − (E X)^ 2

(d) E(X + Y ) = E X + E Y

Solutions

Expert Solution

X is Binomial(n,p). The probability mass function (pmf) of X is

First we calculate the expectation of X

Now the term in the summation corresponds to binomial probability for Y distributed Binomial(n-1,p) with pmf

Since the pmf sums to 1, the summation is equal to 1, that is

Hence

Next we will compute the expected value of E[X(X-1)]

Now the term in the summation corresponds to binomial probability for Y distributed Binomial(n-2,p) with pmf

Since the pmf sums to 1, the summation is equal to 1

That means

But

Now to the variance of X


Related Solutions

Let X be a Bin(100, p) random variable, i.e. X counts the number of successes in...
Let X be a Bin(100, p) random variable, i.e. X counts the number of successes in 100 trials, each having success probability p. Let Y = |X − 50|. Compute the probability distribution of Y.
(a) Let X be a binomial random variable with parameters (n, p). Let Y be a...
(a) Let X be a binomial random variable with parameters (n, p). Let Y be a binomial random variable with parameters (m, p). What is the pdf of the random variable Z=X+Y? (b) Let X and Y be indpenednet random variables. Let Z=X+Y. What is the moment generating function for Z in terms of those for X and Y? Confirm your answer to the previous problem (a) via moment generating functions.
Let X be a random variable such that P(X = 1) = 0.4 and P(X =...
Let X be a random variable such that P(X = 1) = 0.4 and P(X = 0) = 0.6.  Compute Var(X).
Let x be a binomial random variable with n=7 and p=0.7. Find the following. P(X =...
Let x be a binomial random variable with n=7 and p=0.7. Find the following. P(X = 4) P(X < 5) P(X ≥ 4)
Let X be a binomial random variable with parameters n = 5 and p = 0.6....
Let X be a binomial random variable with parameters n = 5 and p = 0.6. a) What is P(X ≥ 1)? b) What is the mean of X? c) What is the standard deviation of X? (Show work)
Let X be a binomial random variable with n = 11 and p = 0.3. Find...
Let X be a binomial random variable with n = 11 and p = 0.3. Find the following values. (Round your answers to three decimal places.) (a)     P(X = 5) (b)     P(X ≥ 5) (c)     P(X > 5) (d)     P(X ≤ 5) (e)     μ = np μ = (f)    σ = npq σ =
1. (Use Computer) Let X represent a binomial random variable with n = 400 and p...
1. (Use Computer) Let X represent a binomial random variable with n = 400 and p = 0.8. Find the following probabilities. (Round your final answers to 4 decimal places.)   Probability   a. P(X ≤ 330)         b. P(X > 340)         c. P(335 ≤ X ≤ 345)         d. P(X = 300)       2. (Use computer) Suppose 38% of recent college graduates plan on pursuing a graduate degree. Twenty three recent college graduates are randomly selected. a. What is the...
Let X represent a binomial random variable with n = 110 and p = 0.19. Find...
Let X represent a binomial random variable with n = 110 and p = 0.19. Find the following probabilities. (Do not round intermediate calculations. Round your final answers to 4 decimal places.) a. P(X ≤ 20)    b. P(X = 10) c. P(X > 30) d. P(X ≥ 25)
Let X represent a binomial random variable with n = 180 and p = 0.23. Find...
Let X represent a binomial random variable with n = 180 and p = 0.23. Find the following probabilities. (Do not round intermediate calculations. Round your final answers to 4 decimal places.) a. P(X less than or equal to 45) b. P(X=35) c. P(X>55) d. P (X greater than or equal to 50)
Let X represent a binomial random variable with n = 380 and p = 0.78. Find...
Let X represent a binomial random variable with n = 380 and p = 0.78. Find the following probabilities. (Round your final answers to 4 decimal places.) Probability a. P(X ≤ 300) b. P(X > 320) c. P(305 ≤ X ≤ 325) d. P( X = 290)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT