Let X be a Bin(100, p) random variable, i.e. X counts the number
of successes in...
Let X be a Bin(100, p) random variable, i.e. X counts the number
of successes in 100 trials, each having success probability p. Let
Y = |X − 50|. Compute the probability distribution of Y.
Let X be a Bin(n, p) random variable. Show that Var(X) = np(1 −
p). Hint: First compute E[X(X − 1)] and then use (c) and (d).
(c) Var(X) = E(X^2 ) − (E X)^ 2
(d) E(X + Y ) = E X + E Y
The pth percentile (0 < p < 100) of a random variable X is
a number m that satisfies FX(m) = p/100. Find the 25th , 50th
(median), and 75th percentiles of the exponential random variable
with parameter λ. Find the same for a normal random variable with
mean µ and standard deviation σ.
A binomial random variable with parameters n and p represents
the number of successes in n independent trials. We can obtain a
binomial random variable by generating n uniform random numbers 1 2
n U ,U ,...,U and letting X be the number of i U that are less than
or equal to p. (a) Write a MATLAB function to implement this
algorithm and name the function gsbinrnd. You may use the for loop
to generate random numbers. (b) Use...
(a) Let X be a binomial random variable with parameters (n, p).
Let Y be a binomial random variable with parameters (m, p).
What is the pdf of the random variable Z=X+Y?
(b) Let X and Y be indpenednet random variables. Let Z=X+Y.
What is the moment generating function for Z in terms of those
for X and Y?
Confirm your answer to the previous problem (a) via moment
generating functions.
Let x be a random variable that represents the pH of
arterial plasma (i.e., acidity of the blood). For healthy adults,
the mean of the x distribution is μ = 7.4.† A new
drug for arthritis has been developed. However, it is thought that
this drug may change blood pH. A random sample of 36 patients with
arthritis took the drug for 3 months. Blood tests showed that
x = 8.6 with sample standard deviation s = 3.5.
Use a...
Let x be a random variable that represents the pH of
arterial plasma (i.e., acidity of the blood). For healthy adults,
the mean of the x distribution is μ = 7.4.† A new
drug for arthritis has been developed. However, it is thought that
this drug may change blood pH. A random sample of 36 patients with
arthritis took the drug for 3 months. Blood tests showed that
x = 8.7 with sample standard deviation s = 3.4.
Use a...
Let x be a random variable that represents the pH of
arterial plasma (i.e., acidity of the blood). For healthy adults,
the mean of the x distribution is μ = 7.4.† A new
drug for arthritis has been developed. However, it is thought that
this drug may change blood pH. A random sample of 36 patients with
arthritis took the drug for 3 months. Blood tests showed that
x = 8.4 with sample standard deviation s = 2.9.
Use a...
Let x be a random variable that represents the pH of
arterial plasma (i.e., acidity of the blood). For healthy adults,
the mean of the x distribution is μ = 7.4.† A new
drug for arthritis has been developed. However, it is thought that
this drug may change blood pH. A random sample of 31 patients with
arthritis took the drug for 3 months. Blood tests showed that
x = 8.7 with sample standard deviation s = 3.0.
Use a...
Let x be a random variable that represents the pH of arterial
plasma (i.e., acidity of the blood). For healthy adults, the mean
of the x distribution is μ = 7.4.† A new drug for arthritis has
been developed. However, it is thought that this drug may change
blood pH. A random sample of 31 patients with arthritis took the
drug for 3 months. Blood tests showed that x = 8.7 with sample
standard deviation s = 3.1. Use a...