In: Statistics and Probability
Instructions:
1. Come up with two example data sets of your own whose standard deviations would be interesting to compare. Some examples:
a) Potato weights vs onion weights.
b) Female heights vs male heights
c) National league batting averages vs American league batting averages
An example that doesn't work: GPAs vs SATs. These are two different variables that even use different units. So comparing their standard deviations is meaningless. However, male GPA vs female GPA would be a valid comparison.
2. Get sample data for the two data sets you chose by measuring, surveying, researching, etc. Sample sizes must be at least 10, but the more the better.
3. Compute the means, standard deviations and variances for the two data sets.
4. Compute the z-score and percentile for two values from each data set (for a total of four z-scores and four percentiles).
Help!
Std Dev =
Z-score =
Dataset 1
SL.no | Male Height | Female Height |
1 | 174 | 161.8 |
2 | 174.6 | 159.6 |
3 | 175.6 | 161.01 |
4 | 177.8 | 158.1 |
5 | 179 | 161.8 |
6 | 180 | 163.8 |
7 | 178.8 | 166 |
8 | 179.2 | 167 |
9 | 171.8 | 167.6 |
10 | 165.1 | 165.4 |
11 | 171 | 154.2 |
12 | 178.7 | 156.6 |
13 | 178.6 | 150.6 |
14 | 183.9 | 168.1 |
Total | 2468.1 | 2261.61 |
Average | 176.2929 | 161.5436 |
Std Dev | 4.716169 | 5.287456 |
Z-score for male height 171 = -1.223 , percentile = P(Z) = 11.067%
Z score for female height 154.2 = -1.388, percentile = P(Z) = 8.25%
Datase-2
Economic Test Scores | ||
SL.no | Male | Female |
59.7 | 59 | |
60.8 | 50.3 | |
68.4 | 49.2 | |
58.2 | 57.5 | |
61 | 55.1 | |
62.8 | 69.5 | |
58.8 | 67.8 | |
58.8 | 59.3 | |
54.8 | 57.5 | |
65 | 62.4 | |
62.3 | 61.2 | |
64.3 | 51.5 | |
Total | 734.9 | 700.3 |
Average | 61.24167 | 58.35833 |
Std Dev | 3.61272 | 6.374161 |
Zscore for male score 65 = 1.040 , percentile = P(Z) = 85.08%
Zscore for female score 65 = 1.042 , percentile = P(Z) = 85.13%