In: Chemistry
In a second experiment, 16.00 g of sodium acetate trihydrate (136.08 g/mol) was dissolved in 100.00 ml of water. The initial temperature was 25.00 °C, and the final temperature was 20.06 ºC. The heat capacity of the reaction mixture was 4.045 J g-1deg-1
E. Calculate delta Hhydration for converting sodium acetate(s) to sodium acetate trihydrate (aq)
1
I've done previous portions of this same question including calcultating delta T, heat transfered, number of moles, and delta H dissolution if that helps to know!
mass of solution = 16.00+ 100 = 116 g
q = msdeltaT
= 116*4.045*(20.06-25)
= - 2317.95 J
moles of sodium acetate trihydrate = 16.00/136.08 = 0.1176 moles
0.1176 moles of sodium acetate gives ----> -2317.95 J
1 mole of sodium acetate gives ------> -2317.95*1/0.1176
= -19710.46 J
= -19.71046 KJ/mol