3.920 g of sodium acetate ( CH3COONa MW= 82.03 g/mol), is dissolved in 235.0ml of H2O...

3.920 g of sodium acetate ( CH3COONa MW= 82.03 g/mol), is dissolved in 235.0ml of H2O at 50 degree celsius (kw= K.48E-14). Calculate the pH of this soluion ( Ka= 1.63 E-5) Determine the % ionization

Solutions

Expert Solution

When CH3COONa is dissolved in water following reaction occur,

CH3COO^- + H2O ---> CH3COOH + OH^-

Kb = Kw/Ka

= 5.48*10^-14/1.63*10^-5

Kb = 3.36*10^-9

[CH3COONa] = moles of CH3COONa / Volume in L

moles = mass/ molar mass

So, moles of CH3COONa = 3.920g/82.03g/mol = 0.0478mol

So, [CH3COONa] = 0.0478mol/0.235L = 0.2034M

Let [ CH3COOH] = [OH^-] = x

So, Kb = [CH3COOH][OH^-] / [CH3COO^-]

3.36*10^-9= x*x/0.2034M

x² = 6.834*10^-8M

x = (6.834*10^-8)^1/2M

x = 2.614*10^-4M

[OH^-] = 2.614*10^-4M

pOH = -log[OH^-]

= -log(2.614*10^-4)

pOH = -log2.614+4log10

= 3.58

pH = 14-pOH = 14-3.58 = 10.4

pH = 10.4

Percent ionization =( [OH^-] / [CH3COONa] )*100

=( 2.614*10^-4M / 0.2034M)*100

= 0.128%

queen_honey_blossom answered 1 year ago

Next > < Previous

Related Solutions

14.00 g of anhydrous sodium acetate (82.03 g/mol) was dissolved in 100.00 g of water, the...

14.00 g of anhydrous sodium acetate (82.03 g/mol) was dissolved in 100.00 g of water, the heat capacity of the reaction mixture was 4.045 J/g K. The change in temperature was increased by 6.40 °C. 1. is this an exothermic or a.m. endothermic reaction? 2. the heat transferred (qsys), was? 3. the number of moles of anhydrous sodium acetate dissolved is? 4. the (delta H) of dissolution for anhydrous sodium acetate is?

In a second experiment, 16.00 g of sodium acetate trihydrate (136.08 g/mol) was dissolved in 100.00...

In a second experiment, 16.00 g of sodium acetate trihydrate (136.08 g/mol) was dissolved in 100.00 ml of water. The initial temperature was 25.00 °C, and the final temperature was 20.06 ºC. The heat capacity of the reaction mixture was 4.045 J g-1deg-1 E. Calculate delta Hhydration for converting sodium acetate(s) to sodium acetate trihydrate (aq) 1 I've done previous portions of this same question including calcultating delta T, heat transfered, number of moles, and delta H dissolution if that...

MW (g/mol) / MP ( oC) / Solubility in cold H2O (g / 100 mL) /...

MW (g/mol) / MP ( oC) / Solubility in cold H2O (g / 100 mL) / Solubility in boiling H2O (g / 100 mL) Acetanilide 135.2 / 114 / 0.54 / 5.0 Phenacetin 179.2 / 135 / 0.076 / 1.22 Using solubility data in the table of reagents, calculate the minimum amount water needed to recrystallize: i. 1.5 g of phenacetin. ii. 1.5 g of acetanilide. b. If the minimum amount of water needed is used, how many grams of...

Calculate the freezing point of a solution of 40.0 g methyl salicylate, (MW: 152.15 g/mol), dissolved...

Calculate the freezing point of a solution of 40.0 g methyl salicylate, (MW: 152.15 g/mol), dissolved in 800. g of benzene, C6H6. Kf of benzene is 5.10 C/m and the freezing point is 5.50°C for benzene.

A 0.7257 g mixture of KCN (MW = 65.116 g/mol) and NaCN (MW = 49.005 g/mol)...

A 0.7257 g mixture of KCN (MW = 65.116 g/mol) and NaCN (MW = 49.005 g/mol) was dissolved in water. AgNO3 was added to the solution, precipitating all the CN– in solution as AgCN (MW = 133.886 g/mol). The dried precipitate weighed 1.650 g. Calculate the weight percent of KCN and NaCN in the original sample.

Acetic acid (molecular weight = 60.05 g/mol) and sodium acetate (molecular weight = 82.03 g/mol) can...

Acetic acid (molecular weight = 60.05 g/mol) and sodium acetate (molecular weight = 82.03 g/mol) can form a buffer with an acidic pH. In a 500.0 mL volumetric flask, the following components were added together and mixed well, and then diluted to the 500.0 mL mark: 100.0 mL of 0.300 M acetic acid, 1.00 g of sodium acetate, and 0.16 g of solid NaOH (molecular weight = 40.00 g/mol). What is the final pH? The Ka value for acetic acid...

What is the pH when 6.1 g of sodium acetate, NaC2H3O2, is dissolved in 250.0 mL...

What is the pH when 6.1 g of sodium acetate, NaC2H3O2, is dissolved in 250.0 mL of water? (The Ka of acetic acid, HC2H3O2, is 1.8×10−5.) Express your answer using two decimal places.

*Calculate the mass of sodium acetate (CH3COONa) required to prepare 50 mL of a 0.10 M...

*Calculate the mass of sodium acetate (CH3COONa) required to prepare 50 mL of a 0.10 M sodium acetate solution. Show work. Verify that this matches the amount you place into cup #3 in Activity 1. *Calculate the volume of 6 M acetic acid needed to prepare 100 mL of a 0.10 M acetic acid (CH3COOH) solution. Show work. *Calculate the volume of 1 M sodium hydroxide (NaOH) needed to prepare 10 mL of a 0.10 M sodium hydroxide solution. Show...

How many grams of sodium lactate (MW = 112 g/mol) are required to prepare 200 ml...

How many grams of sodium lactate (MW = 112 g/mol) are required to prepare 200 ml solution at 1.0 M? Given pKa of lactic acid = 3.86, what is the pH of this solution?

Calculate the mass of sodium acetate trihydrate (CH3COONa●3H2O) solid and the volume of 1.00 M acetic...

Calculate the mass of sodium acetate trihydrate (CH3COONa●3H2O) solid and the volume of 1.00 M acetic acid (CH3COOH) required to make 250.0 mL of 0.100 M buffer, pH 5.00.

Subjects