In: Statistics and Probability
Section Exercise 4-29 Noodles and Company tested consumer reaction to two spaghetti sauces. Each of 70 judges rated both sauces on a scale of 1 (worst) to 10 (best) using several taste criteria. To correct for possible bias in tasting order, half the judges tasted Sauce A first, while the other half tasted Sauce B first. Actual results are shown below for “overall liking.”
Sauce A: 5, 5, 3, 6, 7, 5, 7, 6, 2, 6, 5, 7, 7, 6, 7, 9, 8, 8, 6, 5, 7, 8, 5, 5, 8, 3, 6, 7, 8, 5, 6, 1, 6, 5, 8, 5, 5, 4, 8, 7, 6, 7, 6, 6, 7, 7, 8, 8, 7, 8, 5, 7, 5, 5, 1, 7, 9, 5, 6, 5, 6, 8, 6, 6, 5, 6, 1, 8, 7, 8
Sauce B: 8, 8, 2, 7, 9, 8, 3, 8, 7, 8, 7, 7, 1, 8, 7, 5, 1, 5, 7, 8, 7, 7, 7, 8, 7, 7, 2, 9, 5, 8, 7, 6, 6, 7, 6, 2, 8, 6, 6, 7, 7, 8, 7, 7, 5, 5, 6, 1, 5, 6, 5, 5, 2, 6, 5, 5, 5, 2, 6, 5, 6, 5, 7, 5, 4, 7, 8, 6, 8, 6 Click here for the Excel Data File (a) Calculate the mean and standard deviation for each sample. (Round your answers to 3 decimal places.) x⎯⎯ S Sauce A Sauce B (b) Calculate the coefficient of variation for each sample. (Enter your answer as a percentage rounded to 1 decimal place.) CVA % CVB % (c) What is your conclusion about consumer preferences for the two sauces? On average, consumers seem to prefer Sauce A over Sauce B. On average, consumers seem to prefer Sauce B over Sauce A.
Sauce A | |||||
x | f | fx | x- mean | (x- mean)2 | f*(x- mean)2 |
1 | 3 | 3 | -5.042857143 | 25.43040816 | 76.29122449 |
2 | 1 | 2 | -4.042857143 | 16.34469388 | 16.34469388 |
3 | 2 | 6 | -3.042857143 | 9.258979593 | 18.51795919 |
4 | 1 | 4 | -2.042857143 | 4.173265307 | 4.173265307 |
5 | 17 | 85 | -1.042857143 | 1.087551021 | 18.48836735 |
6 | 16 | 96 | -0.042857143 | 0.001836735 | 0.029387755 |
7 | 15 | 105 | 0.957142857 | 0.916122449 | 13.74183673 |
8 | 13 | 104 | 1.957142857 | 3.830408163 | 49.79530612 |
9 | 2 | 18 | 2.957142857 | 8.744693877 | 17.48938775 |
sum= | 70 | 423 | -9.385714287 | 69.78795919 | 214.8714286 |
MeanA= sum fx / sum f | |||||
Mean A = | 6.042857143 | ||||
SD= sqrt( sum of f*(x- mean)2 ) | SD (A) = | 14.65849339 | |||
CVA=( SDA/ Mean A )*100 | |||||
CVA= | 41.22427169 |
Sauce B | |||||
x | f | fx | x- mean | (x- mean)2 | f*(x- mean)2 |
1 | 3 | 3 | -5.042857143 | 25.43040816 | 76.29122449 |
2 | 5 | 10 | -4.042857143 | 16.34469388 | 81.72346939 |
3 | 1 | 3 | -3.042857143 | 9.258979593 | 9.258979593 |
4 | 1 | 4 | -2.042857143 | 4.173265307 | 4.173265307 |
5 | 14 | 70 | -1.042857143 | 1.087551021 | 15.22571429 |
6 | 12 | 72 | -0.042857143 | 0.001836735 | 0.022040816 |
7 | 19 | 133 | 0.957142857 | 0.916122449 | 17.40632653 |
8 | 13 | 104 | 1.957142857 | 3.830408163 | 49.79530612 |
9 | 2 | 18 | 2.957142857 | 8.744693877 | 17.48938775 |
sum= | 70 | 417 | -9.385714287 | 69.78795919 | 271.3857143 |
MeanB= sum fx / sum f | |||||
MeanB= | 5.957142857 | ||||
SD= sqrt( sum of f*(x- mean)2 ) | SD (B) = | 16.4737887 | |||
CVB=( SDA/ Mean B)*100 | |||||
CVB= | 36.16134068 |
The coefficient of variation (CV) is the ratio of the standard deviation to the mean. The higher the coefficient of variation, the greater the level of dispersion around the mean. The lower the value of the coefficient of variation, the more precise the estimate.
Since CV of sauce B is lees,so we say.
On average, consumers seem to prefer Sauce B over Sauce A.