Two solid metal spheres of different radii are far apart. The spheres are connected by a fine metal wire. Some charge is placed on one of the spheres.

Two solid metal spheres of different radii are far apart. The spheres are connected by a fine metal wire. Some charge is placed on one of the spheres. After electrostatic equilibrium is reached, the wire is removed. Which of these quantities will be the same for the two spheres?

(a) The charge on each sphere
(b) The electric field inside each sphere, at the same distance from the center of the spheres
(c) The electric field just outside the surface of each sphere
(d) The electric potential at the surface of each sphere
(e) Both (b) and (c)
(f) Both (b) and (d)
(g) Both (a) and (c)

Expert Solution

The electric field of a charged sphere shows that the electric field environment outside the sphere is identical to that of a point charge. So the potential is same as that of a point charge.

The electric field inside a solid metal sphere is zero. Since the spheres were connected with a metal wire until the equilibrium was reached, they must have the same electric potential.

The electric potential is,

V = kQ/r

Here, V is the electric potential, r is the distance, and Q is the charge.

Therefore, the electric field inside the each sphere, at the same distance from the center of the spheres and the electric potential at the surface of each sphere are same for both the spheres.

Hence, correct option is (f).

The correct option is (f).

Junaid answered 1 year ago

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