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Two small nonconducting spheres have a total charge of 93.6μC. When placed 1.09 m apart, the...

Two small nonconducting spheres have a total charge of 93.6μC. When placed 1.09 m apart, the force each exerts on the other is 10.9 N and is repulsive.

1. What is the (larger) charge on the spheres?

2. What is the (smaller) charge on the other sphere?

3. What if the force were attractive? What is the larger charge on one of the spheres?

4. What is the smaller charge on the sphere?

Solutions

Expert Solution

Let the two charges be q1 and q2

It is given that

When placed r=1.09 m apart force of repulsion is 10.9 N i.e.,

We know

So, we have

3) If the force was attractive then they will be oppositely charged say +q1 and -q2

Then,

When placed r=1.09 m apart force of attraction is 10.9 N i.e.,

We know

So,

This is the magnitude, so charge q2 is -12.1 micro coulumb

genius_generous answered 2 years ago
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