Question

PART A

A balloon is floating around outside your window. The temperature outside is -19 ∘C , and the air pressure is 0.700 atm . Your neighbor, who released the balloon, tells you that he filled it with 3.00 moles of gas. What is the volume of gas inside this balloon? Express your answer to three significant figures and include the appropriate units.

PART B

A 20.0 L gas cylinder is filled with 7.20 moles of gas. The tank is stored at 9 ∘C . What is the pressure in the tank? Express your answer to three significant figures and include the appropriate units.

PART C

A 240. L kiln is used for vitrifying ceramics. It is currently operating at 1215 ∘C , and the pressure is 0.9250 atm . How many moles of air molecules are within the confines of the kiln? Express your answer to three significant figures and include the appropriate units.

PART D

A 10.0 L gas cylinder has been filled with 4.80 moles of gas. You measure the pressure to be 4.40 atm . What is the temperature inside the tank? Express your answer to three significant figures and include the appropriate units.

Answer 1

PART A

Given

Volume of gas inside the balloon = ?

Temperature of gas = - 19 + 273 = 254 K

Pressure of gas = 0.700 atm

Number of moles of gas = 3.00 mol

We have relation, P V = n R T

where, P is a pressure of a gas, V is a volume of a gas, n is no. of moles of gas, R is a gas constant and T is temperature of gas.

Volume of gas inside the balloon ( V ) = n R T / P

Volume of gas inside the balloon ( V ) = 3.00 0.082057 L atm mol ^-1 K ^-1 254 K / 0.700 atm

Volume of gas inside the balloon ( V ) = 89.3 L

ANSWER : Volume of gas inside the balloon ( V ) = 89.3 L

PART B

Given

Volume of gas = 20.0 L

Temperature of gas =9 + 273 =282 K

Pressure of gas =?

Number of moles of gas = 7.20 mol

We have relation, P V = n R T

Pressure of gas = n R T / V

Pressure of gas = 7.20 0.082057 L atm mol ^-1 K ^-1 282 K / 20.0 L

Pressure of gas = 8.33 atm

ANSWER : Pressure of gas = 8.33 atm

PART C

Given

Volume of gas = 240.0 L

Temperature of gas = 1215 + 273 = 1488 K

Pressure of gas = 0.9250 atm

Number of moles of gas =?

We have relation, P V = n R T

no.of moles of air = P V/ RT

no.of moles of air = 0.9250 atm 240.0 L / 0.082057 L atm mol ^-1 K ^-1 1488 K

no.of moles of air = 1.82 mol

PART D

Given

Volume of gas =10.0 L

Temperature of gas = ?

Pressure of gas =4.40 atm

Number of moles of gas =4.80 mol

We have relation, P V = n R T

temperature of gas inside the tank = P V / n R

temperature of gas inside the tank = 4.40 atm 10.0 L / 0.082057 L atm mol ^-1 K ^-1 4.80 mol

temperature of gas inside the tank = 112 K

temperature of gas inside the tank = 112 K - 273 = - 161 ⁰ C

ANSWER :  temperature of gas inside the tank = - 161 ⁰ C