Question
In: Physics
At 39.9?C, a mixture of ethanol (x1 = 0.9006, p*1 = 130.4 Torr) and isooctane (...
At 39.9?C, a mixture of ethanol (x1 = 0.9006, p*1 = 130.4 Torr) and isooctane ( p*2 = 43.9 Torr) forms a vapor phase with molar fraction y1 = 0.6667 at a total pressure of 185.9 Torr.
(a) Calculate the activity and activity coefficient of each component. Show work
(b) Calculate the total vapor pressure that the mixture would have if it were ideal. Show work
Solutions
genius_generous answered 2 years agoRelated Solutions
Problem 11.93 The vapor pressure of ethanol (C2H5OH) at 19 ∘C is 40.0 torr . A...
Problem 11.93
The vapor pressure of ethanol (C2H5OH) at 19 ∘C is 40.0 torr . A
0.800 g sample of ethanol is placed in a 2.80 L container at 19 ∘C
.
Part A
If the container is closed and the ethanol is allowed to reach
equilibrium with its vapor, how many grams of liquid ethanol
remain?
Express your answer to two significant figures and include the
appropriate units.
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Vapor Pressure of pure ethanol is 40.0 torr at 19 degrees C 3.42g of sugar (C12H22O11,...
Vapor Pressure of pure ethanol is 40.0 torr at 19 degrees C
3.42g of sugar (C12H22O11, non-volatile, non-electrolyte) is
added to 50.0 mL of ethanol (C2H6O, 0.79 g/mL, melting point = -114
degrees C, Kf = 1.99 degrees C/m)
a. Calculate the vapor pressure of the sugar/ethanol solution @
19 degrees C.
b. Calculate the melting point of the sugar/ethanol
solution.
A gaseous mixture contains 421.0 Torr of H2(g), 392.9 Torr of N2(g), and 68.1 Torr of...
A gaseous mixture contains 421.0 Torr of H2(g), 392.9 Torr of
N2(g), and 68.1 Torr of Ar(g). Calculate the mole fraction, X, of
each of these gases.
A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr of N2(g), and 65.7 Torr of...
A gaseous mixture contains 413.0 Torr of H2(g), 391.5 Torr of
N2(g), and 65.7 Torr of Ar(g). Calculate the mole fraction, X, of
each of these gases.
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25...
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2
Torr at 25 °C) form ideal solutions in all proportions. Let x1 and
x2 represent the mole fractions of 1-propanol and 2-propanol in a
liquid mixture, respectively, and y1 and y2 represent the mole
fractions of each in the vapor phase. For a solution of these
liquids with x1 = 0.210, calculate the composition of the vapor
phase at 25 °C.
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25...
1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2
Torr at 25 °C) form ideal solutions in all proportions. Let x1 and
x2 represent the mole fractions of 1-propanol and 2-propanol in a
liquid mixture, respectively, and y1 and y2 represent the mole
fractions of each in the vapor phase. For a solution of these
liquids with x1 = 0.790, calculate the composition of the vapor
phase at 25 °C.
Absolute or 100% ethanol is produced from a mixture of 95% ethanol and 5% water using...
Absolute or 100% ethanol is produced from a mixture of 95%
ethanol and 5% water using the Keyes distillation process. A third
component, benzene, is added to lower the volatility of the
alcohol. Under these conditions, the overhead product is a
constat-boiling mixture of 18.5% ethanol, 7.4% water and 74.1%
benzene. Use the following data to calculate the volume of benzene
that should be fed to the still in order to produce 250 litres of
absolute ethanol: density of 100%...
A solution is composed of 1.50 mol cyclohexane (P∘cy=97.6 torr) and 2.70 mol acetone (P∘ac=229.5 torr)....
A solution is composed of 1.50 mol cyclohexane
(P∘cy=97.6 torr) and 2.70 mol acetone (P∘ac=229.5
torr). What is the total vapor pressure Ptotal above this
solution?
As you saw in Part B, the vapor above the cyclohexane-acetone
solution is composed of both cyclohexane vapor and acetone vapor.
What mole fraction of the vapor above the solution,
Xcy(vapor), is cyclohexane?
A solution is composed of 1.40 mol cyclohexane (P∘cy=97.6 torr) and 2.10 mol acetone (P∘ac=229.5 torr)....
A solution is composed of 1.40 mol cyclohexane
(P∘cy=97.6 torr) and 2.10 mol acetone (P∘ac=229.5
torr). What is the total vapor pressure Ptotal above this
solution?
Ptotal=177torr
As you saw in Part B, the vapor above the cyclohexane-acetone
solution is composed of both cyclohexane vapor and acetone vapor.
What mole fraction of the vapor above the solution,
Xcy(vapor), is cyclohexane?
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr,...
An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has
partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr,
respectively. A quantity of Cl2(g) is injected into the mixture,
and the total pressure jumps to 263.0 Torr (at the moment of
mixing). The system then re-equilibrates. The appropriate chemical
equation is
PCl3(g) + Cl2(g) <---> PCl5(g)
Calculate the new partial pressures after equilibrium is
reestablished.
P PCl3 = ? torr
P PCl2 = ? torr
P PCl5 = ? torr
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