The reaction between sulfur gas (S2) and carbon (C) at high temperatures (900C) results in the...

The reaction between sulfur gas (S₂) and carbon (C) at high temperatures (900C) results in the formation of carbon disulfide (CS₂). The reaction is: C(s) + S₂(g) = CS₂(g). What is the concentration (in moles in reaction chamber) of CS₂(g) at equilibrium if 3.00 moles of S₂(g) and excess carbon are initially added to the 1.00 L reaction chamber? The K_eq for this reaction is 3.50.

Expert Solution

Solution :-

C(s) + S₂(g) = CS₂(g)

Initial concentration of S2= 3.00 mol / 1.00 L = 3.00 M

Equilibrium concentration of the CS2 = ?

Keq = 3.50

Lets make the Ice table

C(s) + S₂(g) ----- > CS₂(g)

3.00 M 0

-x +x

3.00 –x x

Keq = [CS2]/[S2]

3.50 = [x] / [3.00-x]

X= 2.33

Therefore the equilibrium concentration of the CS2(g) = 2.33 M

queen_honey_blossom answered 1 year ago

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