In: Statistics and Probability
A random sample of 28 items is drawn from a population whose standard deviation is unknown. The sample mean is x⎯⎯x¯ = 790 and the sample standard deviation is s = 15. Use Appendix D to find the values of Student’s t. |
(a) |
Construct an interval estimate of μ with 99% confidence. (Round your answers to 3 decimal places.) |
The 99% confidence interval is from to |
(b) |
Construct an interval estimate of μ with 99% confidence, assuming that s = 30. (Round your answers to 3 decimal places.) |
The 99% confidence interval is from to |
(c) |
Construct an interval estimate of μ with 99% confidence, assuming that s = 60. (Round your answers to 3 decimal places.) |
The 99% confidence interval is from to |
(d) |
Describe how the confidence interval changes as s increases. |
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a)
t critical value at 0.01 significance level with 27 df = 2.771
99% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
790 - 2.771 * 15 / sqrt(28) < < 790 + 2.771 * 15 / sqrt(28)
782.145 < < 797.855
99% CI is from 782.145 to 797.855
b)
t critical value at 0.01 significance level with 27 df = 2.771
99% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
790 - 2.771 * 30 / sqrt(28) < < 790 + 2.771 * 30 / sqrt(28)
774.290 < < 805.710
99% CI is from 774.290 to 805.710
c)
t critical value at 0.01 significance level with 27 df = 2.771
99% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
790 - 2.771 * 60 / sqrt(28) < < 790 + 2.771 * 60 / sqrt(28)
758.580 < < 821.420
99% CI is from 758.580 to 821.420
d)
The interval gets wider as S increases.