Question

When testing the claim that the mean is not equal to 25.5 (two sided t-test). Assume sigma is unknown and sample size is 10. Find p-value if test value is 1.45. ( use t- table )?

	5%< p-value <10%
	2%< p-value < 5%
	1%< p-value < 2%
	10%< p-value < 20%
	2.5%< p-value < 5%

Answer 1

When testing the claim that the mean is not equal to 25.5 (two sided t-test). Assume sigma is unknown and sample size is 10. Find p-value if test value is 1.45. ( use t- table )?

Answer :-  10%< p-value < 20%

The complete solution of above question are as below

The values provided in the above question are as below

Sample size = n = 10

test value = t = 1.45

We testing the claim that the mean is not equal to 25.5 (two sided t-test)

We find p-value above test using following Excel function

=TDIST(x,deg_freedom,tails)

Here, We use

x = test value = t = 1.45

deg_freedom = n - 1 = 10 - 1 = 9

tails = 2 (Because the above test is two sided t-test.

Using all values in Excel function is as

=TDIST(1.45,9,2) then press Enter we get p-value is as below

p-value = 0.180996 0.1810 (Round answer up to 4 decimal places)

We express above p-value = 0.1810 in percentage as 18.10%

The above p-value = 0.1810 = 18.10% lies between 10% to 20%

The correct answer of p-value lies between is as 10%< p-value < 20%

It test value is 1.45 then it's p-value is 18.10% and lies between

Answer :- 10%< p-value < 20%

Summary :-

It test value is 1.45 then it's p-value is 0.1810 = 18.10% and lies between

Answer :- 10%< p-value < 20%