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A galaxy’s calcium-H line – normally located at 3968.4673 Å – is observed to have a...

A galaxy’s calcium-H line – normally located at 3968.4673 Å – is observed to have a wavelength of 4074.995 Å. How far away would you calculate this galaxy to be, in Mpc, using a Hubble’s parameter of 72.5?

		106
		8,047
		73
		111
		240
		None of the above is close

Solutions

Expert Solution

Solution:-

Rest wavelength is () = 3968.4673

Observed wavelength is () = 4074.995

Hubble Constant given = 72.5 km/sec/Mpc

Now in order to get recession velocity galaxy we use doppler shift

where v is recession velocity, ? is the rest wavelength, ?? is how much the line has shifted due to the Doppler effect, c = 3×105 km/s is the speed of light.

So recession velocity is:-

By Hubble's Law-

Now substituting values of and -

So the answer is option D.

genius_generous answered 2 years ago

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