A) Six different mutations were derived from base pair substitutions at a single codon. In this...

A) Six different mutations were derived from base pair substitutions at a single codon. In this codon, the mutant alleles had asparagine, glutamic acid, g;lutamine, methionine, arginine, and a stop codon. What was the wild-type codon?

Solutions

Expert Solution

Methionine is encoded only by ATG.

Asparagine is encoded by AAT, AAC

Glutamic acid is encoded by -GAA, GAG

Arginine is encoded by - CGT, CGC, CGA, CGG; AGA, AGG

Glutamine is encoded by - CAA, CAG

Stop codon - TAA, TGA, TAG

If we at most to the codon then the last base is G.

Hence the last base is __G in the codon.

If we look at most of the codon such as AAT, AAC, GAA, GAG, CAA, CAG and TAG, Adenine is present in the middle of the codon.

So the codon is _AG.

If we look at most of the codon such as AGA, AGG, ATG, AAT, AAC, AGA, AGG Adenine is present in the first position of the codon. So the codon is AAG.

AAG can be mutated to - ATG - methionine

AAG can be mutated to AGG - arginine.

AAG can be mutated to CAG -Glutamine

AAG can be mutated to GAG - Glutamic acid

AAG can be mutated to AAT or AAC - Asparagine.

AAG can be mutated to TAG - stop codon.

Hence the wild-type codon is AAG.

Please write to me if you need more help.

gladiator answered 1 year ago

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