Question

In: Chemistry

a student ran the vanillin reduction as shown below. if 5.52 g of vanillinwas used and...

a student ran the vanillin reduction as shown below. if 5.52 g of vanillinwas used and 3.267g of product was obtained. what is tge tgeiretical 100% yeild. what is the actual yeild.
C= 12.01g/mol
H= 1.008 g/mol
O= 16.00g/mol

Solutions

Expert Solution

Ans. Actual yield is 3.267 g,

Theoretical yield is 5.5931g ,p

yeild is 58.41%

Complete answer is given in the picture,for any doubt feel free to ask in the comment box, Give it a Thumbs up, Thank-you!


Related Solutions

Vanillin Reduction with Sodium Borohydride to form Vanillyl Alcohol Started with 2.517g vanillin and 5.0mL NaBH4...
Vanillin Reduction with Sodium Borohydride to form Vanillyl Alcohol Started with 2.517g vanillin and 5.0mL NaBH4 Crude Product= 7.568g Recrystallized Product= 2.297g a) Calculate the %yield for both the crude and "fully" synthesized product b) Explain why this is likely not 100%. How could this be improved c) Draw mechanism
A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) +...
A student ran the following reaction in the laboratory at 445 K : PCl5(g)-------> PCl3(g) + Cl2(g) When she introduced 1.28 moles of PCl5(g) into a 1.00 liter container, she found the equilibrium concentration of PCl5(g) to be 1.24 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
A student ran the following reaction in the laboratory at 684 K: N2(g) + 3H2(g) 2NH3(g)...
A student ran the following reaction in the laboratory at 684 K: N2(g) + 3H2(g) 2NH3(g) When she introduced 3.26×10-2 moles of N2(g) and 6.07×10-2 moles of H2(g) into a 1.00 liter container, she found the equilibrium concentration of H2(g) to be 5.83×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = __
-A student ran the following reaction in the laboratory at 1143 K: 2SO2(g) + O2(g) 2SO3(g)...
-A student ran the following reaction in the laboratory at 1143 K: 2SO2(g) + O2(g) 2SO3(g) When she introduced 8.19×10-2 moles of SO2(g) and 8.56×10-2 moles of O2(g) into a 1.00 liter container, she found the equilibrium concentration of O2(g) to be 6.08×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =____________ -A student ran the following reaction in the laboratory at 363 K: CH4(g) + CCl4(g)      2CH2Cl2(g) When she introduced 4.64×10-2 moles of CH4(g) and...
A student ran the folllowing reaction in the laboratory at 661 K: 2NH3(g) N2(g) + 3H2(g)...
A student ran the folllowing reaction in the laboratory at 661 K: 2NH3(g) N2(g) + 3H2(g) When she introduced NH3(g) at a pressure of 0.597 atm into a 1.00 L evacuated container, she found the equilibrium partial pressure of H2(g) to be 0.879 atm. Calculate the equilibrium constant, Kp, she obtained for this reaction.
A student ran the following reaction in the laboratory at 720 K: H2(g) + I2(g) 2HI(g)...
A student ran the following reaction in the laboratory at 720 K: H2(g) + I2(g) 2HI(g) When she introduced 0.189 moles of H2(g) and 0.218 moles of I2(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 6.05×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 291 K: 2CH2Cl2(g) CH4(g) + CCl4(g)...
A student ran the following reaction in the laboratory at 291 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When she introduced 6.63×10-2 moles of CH2Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of CH2Cl2(g) to be 4.92×10-3 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = _____
A student ran the following reaction in the laboratory at 610 K: CO(g) + Cl2(g) COCl2(g)...
A student ran the following reaction in the laboratory at 610 K: CO(g) + Cl2(g) COCl2(g) When she introduced 0.183 moles of CO(g) and 0.211 moles of Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of Cl2(g) to be 6.72×10-2 M.   Calculate the equilibrium constant, Kc, she obtained for this reaction. 2.A student ran the following reaction in the laboratory at 546 K: COCl2(g) CO(g) + Cl2(g)   When she introduced 0.854 moles of COCl2(g) into a 1.00...
1. A student ran the following reaction in the laboratory at 582 K: CO(g) + Cl2(g)...
1. A student ran the following reaction in the laboratory at 582 K: CO(g) + Cl2(g)      COCl2(g) When she introduced 0.380 moles of CO(g) and 0.403 moles of Cl2(g) into a 1.00 liter container, she found the equilibrium concentration of COCl2(g) to be 0.342 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. 2. The equilibrium constant, Kc, for the following reaction is 1.29×10-3 at 540 K. COCl2(g) CO(g) + Cl2(g) When a sufficiently large sample of COCl2(g)...
Shown below is an oxidation-reduction reaction in acidic solution. Which of the following correctly balances the...
Shown below is an oxidation-reduction reaction in acidic solution. Which of the following correctly balances the reaction? ClO−4+Rb→ClO−3+Rb+ Select the correct answer below: A. ClO−4+Rb+2H+→ClO−3+Rb++H2O B. 2ClO−4+Rb+4H+→2ClO−3+Rb++2H2O C. ClO−4+2Rb+2H+→ClO−3+2Rb++H2O D. ClO−4+3Rb+2H+→ClO−3+3Rb++H2O
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT