In: Computer Science
Sum the odd integers between 1 and 99 using a for structure. Assume the integer variables sum and count have been declared.
Calculate the value of 2.5 raised to the power of 3 using pow method.
Print the integers from 1 to 20 using a while loop and the counter variable x. Assume that the variable x has been declared but not initialized. Print only five integers per line.[ Hint: Use calculation x % 5. When the value of this is 0, print a newline character; otherwise, print a tab character. Assume this is an application- use the System.out.println() method to output the newline character and use the System.out.print( ‘\t’ ) method to output the tab character.]
Repeat Exercise 2 c) using for structure.
public class Calculation { public static void main(String[] args) { int sum=0,i; for(i=3;i<99;i=i+2) { sum=sum+i; } System.out.println("Sum of odd integers between 1 to 99 is "+sum); } }
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public class Calculation { public static void main(String[] args) { float base= (float) 2.5; double result; int exponent=3; result=Math.pow(base,exponent); System.out.println(result); } }
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public class Calculation { public static void main(String[] args) { int x=1; while(x<=20) { System.out.print(x); if(x%5==0) { System.out.println(); } else { System.out.print('\t'); } x++; } } }
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public class Calculation { public static void main(String[] args) { for(int x=1;x<=20;x++) { System.out.print(x); if(x%5==0) { System.out.println(); } else { System.out.print('\t'); } } } }
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