Question

In Coral. Given a sorted list of integers, output the middle integer .Assume the number of integers ia odd. Ex: if the input 2 3 4 8 11 -1(a negative indicates end), the output is 4.
the maximum number of inputs for any test case should not exceed 9 positive values. If exceeded , output Too many inputs". Hint: Use an array of size 9. First read the data into array.Then,based in the number of items, find the middle item.

Answer 1

The logic for this is simple. Keep taking input until -1 is given and for every input, increment the count value (0 indexed) so that when the count becomes 8 (actually 9), it means 9 elements are given so any more input causes "Too many inputs" as output. The code is shown below:

// Create an array of size 9
integer array(9) nums
integer x
integer count

// To check if broke while because of overflow count
integer flag

count = 0

// Initialize it to 0
flag = 0

while x != -1
   x = Get next input
   // If count is 8, required elements are got (9)
   // So no need of any more so to break, put x = -1
   if count == 9
      if x != -1
         x = -1
         flag = 1
      
   // If x is not -1, put in array and increment count
   if x != -1
      nums[count] = x
      count = count + 1
      
// If broke while because of count
if flag == 1
   Put "Too many inputs" to output
else
   Put nums[count/2] to output

A screenshot for indentation purposes which will help you to code clearly is given below:

A screenshot of the output for two different inputs:

and

Hope this is helpful. In case of any queries, please comment below. All the best :)