Using for loop . Input an integer and identify whether it's EVEN OR ODD ( without...

Using for loop . Input an integer and identify whether it's EVEN OR ODD ( without using modulo operator )

using only <iostream> . C++ programming

Expert Solution

#include <iostream>
using namespace std;

// It will return true if n is even. Otherwise odd.
bool isEven(int n)
{
bool isEven = true;
   if(n<0)
n=-n;
for (int i=1; i<=n; i++)
   isEven = !isEven;
return isEven;
}

int main()
{
int n;
   cout<<" Enter an integer:";
   cin>>n;
isEven(n) ? cout << "Even" : cout << "Odd";
return 0;
}

Output:

venereology answered 1 year ago

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